What are the solutions to the equation 7+5b-3b^2=8 ?

The solutions to the equation 7+5b-3b^2=8 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6

Find the zeros of 7+5b-3b^2=8

The zeros of 7+5b-3b^2=8 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6

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7 + 5 b - 3 b^{2} = 8

b = \frac{5 - 13}{6}, b = \frac{5 + 13}{6}

Decimal Notation

b = 0.23240 \dots, b = 1.43425 \dots

Solution steps

7 + 5 b - 3 b^{2} = 8

Move

8

to the left side

- 3 b^{2} + 5 b - 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

5^{2} - 4 (- 3) (- 1) = 13

b_{1, 2} = \frac{- 5 \pm 13}{2 ( - 3 )}

Separate the solutions

b_{1} = \frac{- 5 + 13}{2 ( - 3 )}, b_{2} = \frac{- 5 - 13}{2 ( - 3 )}

b = \frac{- 5 + 13}{2 ( - 3 )} : \frac{5 - 13}{6}

b = \frac{- 5 - 13}{2 ( - 3 )} : \frac{5 + 13}{6}

The solutions to the quadratic equation are:

b = \frac{5 - 13}{6}, b = \frac{5 + 13}{6}

\frac{50 + 8}{20 - 7}

2 w^{2} - 4 w + 5 = 0

- 2 = - 2 x + 4

3 x^{2} + 48

4 x^{2} - 16 x + 14 = 0

What are the solutions to the equation 7+5b-3b^2=8 ?
The solutions to the equation 7+5b-3b^2=8 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6
Find the zeros of 7+5b-3b^2=8
The zeros of 7+5b-3b^2=8 are b=(5-sqrt(13))/6 ,b=(5+sqrt(13))/6