What are the solutions to the equation 3x^2-7x+7=0 ?

The solutions to the equation 3x^2-7x+7=0 are x= 7/6+i(sqrt(35))/6 ,x= 7/6-i(sqrt(35))/6

Find the zeros of 3x^2-7x+7=0

The zeros of 3x^2-7x+7=0 are x= 7/6+i(sqrt(35))/6 ,x= 7/6-i(sqrt(35))/6

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3 x^{2} - 7 x + 7 = 0

x = \frac{7}{6} + i \frac{35}{6}, x = \frac{7}{6} - i \frac{35}{6}

Solution steps

3 x^{2} - 7 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

(- 7)^{2} - 4 \cdot 3 \cdot 7 : 35 i

x_{1, 2} = \frac{- ( - 7 ) \pm 35 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 35 i}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 35 i}{2 \cdot 3}

x = \frac{- ( - 7 ) + 35 i}{2 \cdot 3} : \frac{7}{6} + i \frac{35}{6}

x = \frac{- ( - 7 ) - 35 i}{2 \cdot 3} : \frac{7}{6} - i \frac{35}{6}

The solutions to the quadratic equation are:

x = \frac{7}{6} + i \frac{35}{6}, x = \frac{7}{6} - i \frac{35}{6}

\frac{x}{7} \geq 1 - \frac{x}{14}

x^{2} - 225

x + 2 = 36

343 b^{2} - 7 b^{4}

\frac{y}{9} = \frac{44}{54}

What are the solutions to the equation 3x^2-7x+7=0 ?
The solutions to the equation 3x^2-7x+7=0 are x= 7/6+i(sqrt(35))/6 ,x= 7/6-i(sqrt(35))/6
Find the zeros of 3x^2-7x+7=0
The zeros of 3x^2-7x+7=0 are x= 7/6+i(sqrt(35))/6 ,x= 7/6-i(sqrt(35))/6