What are the solutions to the equation 2x^2+15x=8x-5 ?

The solutions to the equation 2x^2+15x=8x-5 are x=-1,x=-5/2

Find the zeros of 2x^2+15x=8x-5

The zeros of 2x^2+15x=8x-5 are x=-1,x=-5/2

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2 x^{2} + 15 x = 8 x - 5

x = - 1, x = - \frac{5}{2}

Decimal Notation

x = - 1, x = - 2.5

Solution steps

2 x^{2} + 15 x = 8 x - 5

Move

5

to the left side

2 x^{2} + 15 x + 5 = 8 x

Move

8 x

to the left side

2 x^{2} + 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 5 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 2}, x_{2} = \frac{- 7 - 3}{2 \cdot 2}

x = \frac{- 7 + 3}{2 \cdot 2} : - 1

x = \frac{- 7 - 3}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{5}{2}

\frac{8}{3} - 8

2 (- 2) - 1

216

∣ p - 0.53 ∣ \leq 0.03

∣ a + 9 ∣ + 2 \leq 6

What are the solutions to the equation 2x^2+15x=8x-5 ?
The solutions to the equation 2x^2+15x=8x-5 are x=-1,x=-5/2
Find the zeros of 2x^2+15x=8x-5
The zeros of 2x^2+15x=8x-5 are x=-1,x=-5/2