What are the solutions to the equation 9x^2-7x-5=0 ?

The solutions to the equation 9x^2-7x-5=0 are x=(7+sqrt(229))/(18),x=(7-sqrt(229))/(18)

Find the zeros of 9x^2-7x-5=0

The zeros of 9x^2-7x-5=0 are x=(7+sqrt(229))/(18),x=(7-sqrt(229))/(18)

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9 x^{2} - 7 x - 5 = 0

x = \frac{7 + 229}{18}, x = \frac{7 - 229}{18}

Decimal Notation

x = 1.22959 \dots, x = - 0.45181 \dots

Solution steps

9 x^{2} - 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 9 ( - 5 )}{2 \cdot 9}

(- 7)^{2} - 4 \cdot 9 (- 5) = 229

x_{1, 2} = \frac{- ( - 7 ) \pm 229}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 229}{2 \cdot 9}, x_{2} = \frac{- ( - 7 ) - 229}{2 \cdot 9}

x = \frac{- ( - 7 ) + 229}{2 \cdot 9} : \frac{7 + 229}{18}

x = \frac{- ( - 7 ) - 229}{2 \cdot 9} : \frac{7 - 229}{18}

The solutions to the quadratic equation are:

x = \frac{7 + 229}{18}, x = \frac{7 - 229}{18}

\frac{( 300 P + 6000 )}{300 P} = 35%

\frac{- 6 x ^{2} - 2 e ^{y}}{3 x ^{2} y + e ^{y}}

3 x^{2} + 17 x - 28

- {4 (d + 3) - 5 [3 d - 2 (2 d + 7)] - 8} = - 10 d - 6

81 \cdot 9

What are the solutions to the equation 9x^2-7x-5=0 ?
The solutions to the equation 9x^2-7x-5=0 are x=(7+sqrt(229))/(18),x=(7-sqrt(229))/(18)
Find the zeros of 9x^2-7x-5=0
The zeros of 9x^2-7x-5=0 are x=(7+sqrt(229))/(18),x=(7-sqrt(229))/(18)