What are the solutions to the equation x^2-x-16=0 ?

The solutions to the equation x^2-x-16=0 are x=(1+sqrt(65))/2 ,x=(1-sqrt(65))/2

Find the zeros of x^2-x-16=0

The zeros of x^2-x-16=0 are x=(1+sqrt(65))/2 ,x=(1-sqrt(65))/2

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x^{2} - x - 16 = 0

x = \frac{1 + 65}{2}, x = \frac{1 - 65}{2}

Decimal Notation

x = 4.53112 \dots, x = - 3.53112 \dots

Solution steps

x^{2} - x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 16) = 65

x_{1, 2} = \frac{- ( - 1 ) \pm 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 65}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 65}{2 \cdot 1}

x = \frac{- ( - 1 ) + 65}{2 \cdot 1} : \frac{1 + 65}{2}

x = \frac{- ( - 1 ) - 65}{2 \cdot 1} : \frac{1 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 65}{2}, x = \frac{1 - 65}{2}

\frac{4}{9} + \frac{1}{6}

(x - 5)^{2} + 8 (x - 5) + 12

w^{2} + 9 w + 20 = 0

5 - 5 x^{2}

lo g_{10} (100000)

What are the solutions to the equation x^2-x-16=0 ?
The solutions to the equation x^2-x-16=0 are x=(1+sqrt(65))/2 ,x=(1-sqrt(65))/2
Find the zeros of x^2-x-16=0
The zeros of x^2-x-16=0 are x=(1+sqrt(65))/2 ,x=(1-sqrt(65))/2