What are the solutions to the equation -14a-a^2=0 ?

The solutions to the equation -14a-a^2=0 are a=-14,a=0

Find the zeros of -14a-a^2=0

The zeros of -14a-a^2=0 are a=-14,a=0

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- 14 a - a^{2} = 0

a = - 14, a = 0

Solution steps

- 14 a - a^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- a^{2} - 14 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 14)^{2} - 4 (- 1) \cdot 0 = 14

a_{1, 2} = \frac{- ( - 14 ) \pm 14}{2 ( - 1 )}

Separate the solutions

a_{1} = \frac{- ( - 14 ) + 14}{2 ( - 1 )}, a_{2} = \frac{- ( - 14 ) - 14}{2 ( - 1 )}

a = \frac{- ( - 14 ) + 14}{2 ( - 1 )} : - 14

a = \frac{- ( - 14 ) - 14}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

a = - 14, a = 0

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What are the solutions to the equation -14a-a^2=0 ?
The solutions to the equation -14a-a^2=0 are a=-14,a=0
Find the zeros of -14a-a^2=0
The zeros of -14a-a^2=0 are a=-14,a=0