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Popular >

x^2+12x-28=0

Solution

x^{2} + 12 x - 28 = 0

Solution

x = 2, x = - 14

Solution steps

x^{2} + 12 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 28) = 16

x_{1, 2} = \frac{- 12 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 16}{2 \cdot 1}, x_{2} = \frac{- 12 - 16}{2 \cdot 1}

x = \frac{- 12 + 16}{2 \cdot 1} : 2

x = \frac{- 12 - 16}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 2, x = - 14

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Frequently Asked Questions (FAQ)

What are the solutions to the equation x^2+12x-28=0 ?
The solutions to the equation x^2+12x-28=0 are x=2,x=-14
Find the zeros of x^2+12x-28=0
The zeros of x^2+12x-28=0 are x=2,x=-14