What are the solutions to the equation (x-5/2)^2=2+25/4 ?

The solutions to the equation (x-5/2)^2=2+25/4 are x=(sqrt(33)+5)/2 ,x=(-sqrt(33)+5)/2

Find the zeros of (x-5/2)^2=2+25/4

The zeros of (x-5/2)^2=2+25/4 are x=(sqrt(33)+5)/2 ,x=(-sqrt(33)+5)/2

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(x - \frac{5}{2})^{2} = 2 + \frac{25}{4}

x = \frac{33 + 5}{2}, x = \frac{- 33 + 5}{2}

Decimal Notation

x = 5.37228 \dots, x = - 0.37228 \dots

Solution steps

(x - \frac{5}{2})^{2} = 2 + \frac{25}{4}

Simplify

2 + \frac{25}{4} : \frac{33}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - \frac{5}{2} = \frac{33}{4} : x = \frac{33 + 5}{2}

Solve

x - \frac{5}{2} = - \frac{33}{4} : x = \frac{- 33 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{33 + 5}{2}, x = \frac{- 33 + 5}{2}

x^{2} + 13 x + 42

7 = \frac{n - 73}{2}

3 y^{3} - 81

x^{2} y^{2}

\frac{3}{4} + \frac{5}{10}

What are the solutions to the equation (x-5/2)^2=2+25/4 ?
The solutions to the equation (x-5/2)^2=2+25/4 are x=(sqrt(33)+5)/2 ,x=(-sqrt(33)+5)/2
Find the zeros of (x-5/2)^2=2+25/4
The zeros of (x-5/2)^2=2+25/4 are x=(sqrt(33)+5)/2 ,x=(-sqrt(33)+5)/2