What are the solutions to the equation 8x^2+4x=0 ?

The solutions to the equation 8x^2+4x=0 are x=0,x=-1/2

Find the zeros of 8x^2+4x=0

The zeros of 8x^2+4x=0 are x=0,x=-1/2

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8 x^{2} + 4 x = 0

x = 0, x = - \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5

Solution steps

8 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

4^{2} - 4 \cdot 8 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 8}, x_{2} = \frac{- 4 - 4}{2 \cdot 8}

x = \frac{- 4 + 4}{2 \cdot 8} : 0

x = \frac{- 4 - 4}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{2}

- 5 t^{2} + 100 t + 40

5 r^{2} s^{2} (- 2 r^{2} + 3 rs - 4 s^{2})

6 3^{2}

(2 x + 1)^{2} - 6 = 0

6 x^{2} + x - 5

What are the solutions to the equation 8x^2+4x=0 ?
The solutions to the equation 8x^2+4x=0 are x=0,x=-1/2
Find the zeros of 8x^2+4x=0
The zeros of 8x^2+4x=0 are x=0,x=-1/2