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Popular >

15x<= x^2+56

Solution

15 x \leq x^{2} + 56

Solution

x \leq 7 or x \geq 8

+1

Interval Notation

(- \infty, 7] \cup [8, \infty)

Solution steps

15 x \leq x^{2} + 56

Rewrite in standard form

15 x - 56 - x^{2} \leq 0

Factor

15 x - 56 - x^{2} : - (x - 7) (x - 8)

- (x - 7) (x - 8) \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 7) (x - 8)) (- 1) \geq 0 \cdot (- 1)

Simplify

(x - 7) (x - 8) \geq 0

Identify the intervals

x \leq 7 or x \geq 8

Popular Examples

- 3 x - 10 < 21 + 8 x

(y^{3/2})/(y^{1/2)+2}

\frac{y ^{\frac{3}{2}}}{y ^{\frac{1}{2}} + 2}

x(x-2)(x+4)<= 0

x (x - 2) (x + 4) \leq 0

factor 6x^2+18x+12 factor

6 x^{2} + 18 x + 12

∣ 2 x - 4 ∣ + 13 < 5

Frequently Asked Questions (FAQ)

What is 15x<= x^2+56 ?
The solution to 15x<= x^2+56 is x<= 7\lor x>= 8