What are the solutions to the equation 5z^2+z+2=0 ?

The solutions to the equation 5z^2+z+2=0 are z=-1/10+i(sqrt(39))/(10),z=-1/10-i(sqrt(39))/(10)

Find the zeros of 5z^2+z+2=0

The zeros of 5z^2+z+2=0 are z=-1/10+i(sqrt(39))/(10),z=-1/10-i(sqrt(39))/(10)

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5 z^{2} + z + 2 = 0

z = - \frac{1}{10} + i \frac{39}{10}, z = - \frac{1}{10} - i \frac{39}{10}

Solution steps

5 z^{2} + z + 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

Simplify

1^{2} - 4 \cdot 5 \cdot 2 : 39 i

z_{1, 2} = \frac{- 1 \pm 39 i}{2 \cdot 5}

Separate the solutions

z_{1} = \frac{- 1 + 39 i}{2 \cdot 5}, z_{2} = \frac{- 1 - 39 i}{2 \cdot 5}

z = \frac{- 1 + 39 i}{2 \cdot 5} : - \frac{1}{10} + i \frac{39}{10}

z = \frac{- 1 - 39 i}{2 \cdot 5} : - \frac{1}{10} - i \frac{39}{10}

The solutions to the quadratic equation are:

z = - \frac{1}{10} + i \frac{39}{10}, z = - \frac{1}{10} - i \frac{39}{10}

- \frac{10}{- 4}

\frac{x}{8} = 20

\frac{1}{3} (8)^{- \frac{2}{3}}

- 5 v + 6 = - 12 v + 62

What are the solutions to the equation 5z^2+z+2=0 ?
The solutions to the equation 5z^2+z+2=0 are z=-1/10+i(sqrt(39))/(10),z=-1/10-i(sqrt(39))/(10)
Find the zeros of 5z^2+z+2=0
The zeros of 5z^2+z+2=0 are z=-1/10+i(sqrt(39))/(10),z=-1/10-i(sqrt(39))/(10)