What are the solutions to the equation 3d^2+8d-3=0 ?

The solutions to the equation 3d^2+8d-3=0 are d= 1/3 ,d=-3

Find the zeros of 3d^2+8d-3=0

The zeros of 3d^2+8d-3=0 are d= 1/3 ,d=-3

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3 d^{2} + 8 d - 3 = 0

d = \frac{1}{3}, d = - 3

Decimal Notation

d = 0.33333 \dots, d = - 3

Solution steps

3 d^{2} + 8 d - 3 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 3) = 10

d_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- 8 + 10}{2 \cdot 3}, d_{2} = \frac{- 8 - 10}{2 \cdot 3}

d = \frac{- 8 + 10}{2 \cdot 3} : \frac{1}{3}

d = \frac{- 8 - 10}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

d = \frac{1}{3}, d = - 3

6 x^{2} + 17 x + 5 = 0

x = 3 x - 4

3 y^{2} + 2 y - 1 = 0

3969

2 n^{2} + 17 n - 30

What are the solutions to the equation 3d^2+8d-3=0 ?
The solutions to the equation 3d^2+8d-3=0 are d= 1/3 ,d=-3
Find the zeros of 3d^2+8d-3=0
The zeros of 3d^2+8d-3=0 are d= 1/3 ,d=-3