What are the solutions to the equation x^2-8x+24=0 ?

The solutions to the equation x^2-8x+24=0 are x=4+2sqrt(2)i,x=4-2sqrt(2)i

Find the zeros of x^2-8x+24=0

The zeros of x^2-8x+24=0 are x=4+2sqrt(2)i,x=4-2sqrt(2)i

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x^{2} - 8 x + 24 = 0

x = 4 + 22 i, x = 4 - 22 i

Solution steps

x^{2} - 8 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 24 : 42 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 2 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 2 i}{2 \cdot 1} : 4 + 22 i

x = \frac{- ( - 8 ) - 4 2 i}{2 \cdot 1} : 4 - 22 i

The solutions to the quadratic equation are:

x = 4 + 22 i, x = 4 - 22 i

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\frac{5}{2} (x + \frac{1}{3}) - \frac{5}{3} = \frac{83}{12} + \frac{2}{7} x

∣ 8 - 7 x ∣ = 8

9 0^{2} + 9 0^{2} = x^{2}

4 x^{2} - 6 x + 30

What are the solutions to the equation x^2-8x+24=0 ?
The solutions to the equation x^2-8x+24=0 are x=4+2sqrt(2)i,x=4-2sqrt(2)i
Find the zeros of x^2-8x+24=0
The zeros of x^2-8x+24=0 are x=4+2sqrt(2)i,x=4-2sqrt(2)i