What are the solutions to the equation 2x^2-2x-60=0 ?

The solutions to the equation 2x^2-2x-60=0 are x=6,x=-5

Find the zeros of 2x^2-2x-60=0

The zeros of 2x^2-2x-60=0 are x=6,x=-5

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2 x^{2} - 2 x - 60 = 0

x = 6, x = - 5

Solution steps

2 x^{2} - 2 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 60) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 22}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 22}{2 \cdot 2}

x = \frac{- ( - 2 ) + 22}{2 \cdot 2} : 6

x = \frac{- ( - 2 ) - 22}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = 6, x = - 5

x + 8 \leq - \frac{1}{2} or x + 8 \geq \frac{1}{2}

\frac{39.2 \cdot 1 0 ^{- 6}}{8.85 \cdot 1 0 ^{- 12}}

a^{2} - 5 a + 4

3 x + 5 = 4 x^{2} + x

6 x^{2} - x = 5

What are the solutions to the equation 2x^2-2x-60=0 ?
The solutions to the equation 2x^2-2x-60=0 are x=6,x=-5
Find the zeros of 2x^2-2x-60=0
The zeros of 2x^2-2x-60=0 are x=6,x=-5