What are the solutions to the equation -3x^2-2x=2 ?

The solutions to the equation -3x^2-2x=2 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3

Find the zeros of -3x^2-2x=2

The zeros of -3x^2-2x=2 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 2 x = 2

x = - \frac{1}{3} - i \frac{5}{3}, x = - \frac{1}{3} + i \frac{5}{3}

Solution steps

- 3 x^{2} - 2 x = 2

Move

2

to the left side

- 3 x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

Simplify

(- 2)^{2} - 4 (- 3) (- 2) : 25 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 5 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 5 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 2 5 i}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 2 5 i}{2 ( - 3 )} : - \frac{1}{3} - i \frac{5}{3}

x = \frac{- ( - 2 ) - 2 5 i}{2 ( - 3 )} : - \frac{1}{3} + i \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} - i \frac{5}{3}, x = - \frac{1}{3} + i \frac{5}{3}

(x + 1) (x - 4) = 0

20 - 2 (- 8 + 5)

3 x + 7 = 4 x - 3

- 2 = \frac{3 x}{5} + 1

5 x^{2} - 9 x + 4 = 0

What are the solutions to the equation -3x^2-2x=2 ?
The solutions to the equation -3x^2-2x=2 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3
Find the zeros of -3x^2-2x=2
The zeros of -3x^2-2x=2 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3