What are the solutions to the equation (-24/25)^2+y^2=1 ?

The solutions to the equation (-24/25)^2+y^2=1 are y= 7/25 ,y=-7/25

Find the zeros of (-24/25)^2+y^2=1

The zeros of (-24/25)^2+y^2=1 are y= 7/25 ,y=-7/25

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(- \frac{24}{25})^{2} + y^{2} = 1

y = \frac{7}{25}, y = - \frac{7}{25}

Decimal Notation

y = 0.28, y = - 0.28

Solution steps

(- \frac{24}{25})^{2} + y^{2} = 1

Expand

(- \frac{24}{25})^{2} + y^{2} : \frac{576}{625} + y^{2}

\frac{576}{625} + y^{2} = 1

Move

\frac{576}{625}

to the right side

y^{2} = 1 - \frac{576}{625}

Simplify

1 - \frac{576}{625} : \frac{49}{625}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{49}{625}, y = - \frac{49}{625}

\frac{49}{625} = \frac{7}{25}

- \frac{49}{625} = - \frac{7}{25}

y = \frac{7}{25}, y = - \frac{7}{25}

3 a^{3} - 9 a^{2} - 54 a

x^{3} - z^{3}

- 30 x - 25 = 9 x^{2}

0 \leq x - 1 \leq 2 x + 2

30 x^{2} + 42 x

What are the solutions to the equation (-24/25)^2+y^2=1 ?
The solutions to the equation (-24/25)^2+y^2=1 are y= 7/25 ,y=-7/25
Find the zeros of (-24/25)^2+y^2=1
The zeros of (-24/25)^2+y^2=1 are y= 7/25 ,y=-7/25