What are the solutions to the equation 1^2+1^2=x^2 ?

The solutions to the equation 1^2+1^2=x^2 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 1^2+1^2=x^2

The zeros of 1^2+1^2=x^2 are x=sqrt(2),x=-sqrt(2)

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1^{2} + 1^{2} = x^{2}

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

1^{2} + 1^{2} = x^{2}

Switch sides

x^{2} = 1^{2} + 1^{2}

Simplify

1^{2} + 1^{2} : 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

x^{2} + 12 x + 40 = 8

- 15 a + 40

(x + 1) (x - 2) = 4

(x - 5) (5 x - 3) = 0

3 x - 1 = 2 x^{2}

What are the solutions to the equation 1^2+1^2=x^2 ?
The solutions to the equation 1^2+1^2=x^2 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 1^2+1^2=x^2
The zeros of 1^2+1^2=x^2 are x=sqrt(2),x=-sqrt(2)