What are the solutions to the equation 8-x^2=7x ?

The solutions to the equation 8-x^2=7x are x=-8,x=1

Find the zeros of 8-x^2=7x

The zeros of 8-x^2=7x are x=-8,x=1

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8 - x^{2} = 7 x

x = - 8, x = 1

Solution steps

8 - x^{2} = 7 x

Move

7 x

to the left side

8 - x^{2} - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 7 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 1 ) \cdot 8}{2 ( - 1 )}

(- 7)^{2} - 4 (- 1) \cdot 8 = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 ( - 1 )}, x_{2} = \frac{- ( - 7 ) - 9}{2 ( - 1 )}

x = \frac{- ( - 7 ) + 9}{2 ( - 1 )} : - 8

x = \frac{- ( - 7 ) - 9}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 8, x = 1

x^{2} - x - 6

3 (\frac{10}{0.082 \cdot 400}) \cdot (0.81)

9 = \frac{1}{4} (6 x + 12)

\frac{2 x}{1 - x} > 5

5 (\frac{3}{2})

What are the solutions to the equation 8-x^2=7x ?
The solutions to the equation 8-x^2=7x are x=-8,x=1
Find the zeros of 8-x^2=7x
The zeros of 8-x^2=7x are x=-8,x=1