What are the solutions to the equation 2x^2-0.75x-0.5=0 ?

The solutions to the equation 2x^2-0.75x-0.5=0 are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)

Find the zeros of 2x^2-0.75x-0.5=0

The zeros of 2x^2-0.75x-0.5=0 are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 0.75 x - 0.5 = 0

x = \frac{3 + 73}{16}, x = \frac{3 - 73}{16}

Decimal Notation

x = 0.72150 \dots, x = - 0.34650 \dots

Solution steps

2 x^{2} - 0.75 x - 0.5 = 0

Multiply both sides by

100

200 x^{2} - 75 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 75 ) \pm ( - 75 ) ^{2} - 4 \cdot 200 ( - 50 )}{2 \cdot 200}

(- 75)^{2} - 4 \cdot 200 (- 50) = 2573

x_{1, 2} = \frac{- ( - 75 ) \pm 25 73}{2 \cdot 200}

Separate the solutions

x_{1} = \frac{- ( - 75 ) + 25 73}{2 \cdot 200}, x_{2} = \frac{- ( - 75 ) - 25 73}{2 \cdot 200}

x = \frac{- ( - 75 ) + 25 73}{2 \cdot 200} : \frac{3 + 73}{16}

x = \frac{- ( - 75 ) - 25 73}{2 \cdot 200} : \frac{3 - 73}{16}

The solutions to the quadratic equation are:

x = \frac{3 + 73}{16}, x = \frac{3 - 73}{16}

\frac{2}{3} = \frac{1}{4} (- 12 n + 8)

\frac{x}{x + 1} < 1

3 x^{2} - 10 x + 4 = 0

x + \frac{3}{4} < \frac{5 x - 2}{3} + 1

12 x^{2} - 46 x - 8

What are the solutions to the equation 2x^2-0.75x-0.5=0 ?
The solutions to the equation 2x^2-0.75x-0.5=0 are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)
Find the zeros of 2x^2-0.75x-0.5=0
The zeros of 2x^2-0.75x-0.5=0 are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)