What are the solutions to the equation -x^2-8x-15=0 ?

The solutions to the equation -x^2-8x-15=0 are x=-5,x=-3

Find the zeros of -x^2-8x-15=0

The zeros of -x^2-8x-15=0 are x=-5,x=-3

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- x^{2} - 8 x - 15 = 0

x = - 5, x = - 3

Solution steps

- x^{2} - 8 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) ( - 15 )}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) (- 15) = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 2}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 2}{2 ( - 1 )} : - 5

x = \frac{- ( - 8 ) - 2}{2 ( - 1 )} : - 3

The solutions to the quadratic equation are:

x = - 5, x = - 3

4 k - 14 + 3 k = 21

x^{2} - 10 x + 43 = 0

(x + 2) (x - 4) < 0

x^{2} + 4 x - 5 < 0

4 x \geq - 4

What are the solutions to the equation -x^2-8x-15=0 ?
The solutions to the equation -x^2-8x-15=0 are x=-5,x=-3
Find the zeros of -x^2-8x-15=0
The zeros of -x^2-8x-15=0 are x=-5,x=-3