What is factor 12y^2-4y-5 ?

The solution to factor 12y^2-4y-5 is (2y+1)(6y-5)

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factor 12y^2-4y-5

factor

12 y^{2} - 4 y - 5

(2 y + 1) (6 y - 5)

Solution steps

12 y^{2} - 4 y - 5

Break the expression into groups

= (12 y^{2} + 6 y) + (- 10 y - 5)

Factor out

6 y

from

12 y^{2} + 6 y : 6 y (2 y + 1)

Factor out

- 5

from

- 10 y - 5 : - 5 (2 y + 1)

= 6 y (2 y + 1) - 5 (2 y + 1)

Factor out common term

2 y + 1

= (2 y + 1) (6 y - 5)

\frac{( \frac{2}{5} )}{( \frac{2}{3} )}

(\frac{1}{x})^{2}

1^{2} + 4^{2}

\frac{1}{6 ^{4}}

k^{2} - 3 k + 2