What are the solutions to the equation 4x^2+4x+11=0 ?

The solutions to the equation 4x^2+4x+11=0 are x=-1/2+isqrt(5/2),x=-1/2-isqrt(5/2)

Find the zeros of 4x^2+4x+11=0

The zeros of 4x^2+4x+11=0 are x=-1/2+isqrt(5/2),x=-1/2-isqrt(5/2)

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4 x^{2} + 4 x + 11 = 0

x = - \frac{1}{2} + i \frac{5}{2}, x = - \frac{1}{2} - i \frac{5}{2}

Solution steps

4 x^{2} + 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 11}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 11 : 410 i

x_{1, 2} = \frac{- 4 \pm 4 10 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 10 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 10 i}{2 \cdot 4}

x = \frac{- 4 + 4 10 i}{2 \cdot 4} : - \frac{1}{2} + i \frac{5}{2}

x = \frac{- 4 - 4 10 i}{2 \cdot 4} : - \frac{1}{2} - i \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{5}{2}, x = - \frac{1}{2} - i \frac{5}{2}

x^{2} - x y - 5 x + 5 y

9 x + 4 \leq 103

x^{2} - 4 x - 5 \geq 0

2 x + 2 \leq 8 or 4 x + 1 > - 11

- x^{2} - 2 x + 6 = 0

What are the solutions to the equation 4x^2+4x+11=0 ?
The solutions to the equation 4x^2+4x+11=0 are x=-1/2+isqrt(5/2),x=-1/2-isqrt(5/2)
Find the zeros of 4x^2+4x+11=0
The zeros of 4x^2+4x+11=0 are x=-1/2+isqrt(5/2),x=-1/2-isqrt(5/2)