What are the solutions to the equation (2x+7)(2x-7)=0 ?

The solutions to the equation (2x+7)(2x-7)=0 are x=-7/2 ,x= 7/2

Find the zeros of (2x+7)(2x-7)=0

The zeros of (2x+7)(2x-7)=0 are x=-7/2 ,x= 7/2

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(2 x + 7) (2 x - 7) = 0

x = - \frac{7}{2}, x = \frac{7}{2}

Decimal Notation

x = - 3.5, x = 3.5

Solution steps

(2 x + 7) (2 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 7 = 0 or 2 x - 7 = 0

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

Solve

2 x - 7 = 0 : x = \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{7}{2}, x = \frac{7}{2}

\frac{( 1 + i ) ( 1 - i ) ^{4}}{( 1 + 2 i ) ^{3}}

∣ x ∣ \geq 9

1 < 3 x - 2 < 4

2 + 2 p \leq 10

- \frac{30}{6}

What are the solutions to the equation (2x+7)(2x-7)=0 ?
The solutions to the equation (2x+7)(2x-7)=0 are x=-7/2 ,x= 7/2
Find the zeros of (2x+7)(2x-7)=0
The zeros of (2x+7)(2x-7)=0 are x=-7/2 ,x= 7/2