What are the solutions to the equation 1x^2+2x+3=0 ?

The solutions to the equation 1x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

Find the zeros of 1x^2+2x+3=0

The zeros of 1x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

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1 x^{2} + 2 x + 3 = 0

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

1 \cdot x^{2} + 2 x + 3 = 0

Refine

x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

2 x - \frac{1}{2} \geq 7 x + \frac{7}{6}

\frac{4}{9} - \frac{5}{8} (\frac{1}{3})^{2}

∣ x - 3 ∣ = - 2

- 6150

16 x^{2} + 83 = - 72 x

What are the solutions to the equation 1x^2+2x+3=0 ?
The solutions to the equation 1x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i
Find the zeros of 1x^2+2x+3=0
The zeros of 1x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i