What are the solutions to the equation -5p^2-40p=64 ?

The solutions to the equation -5p^2-40p=64 are p=-(4(5+sqrt(5)))/5 ,p=-(4(5-sqrt(5)))/5

Find the zeros of -5p^2-40p=64

The zeros of -5p^2-40p=64 are p=-(4(5+sqrt(5)))/5 ,p=-(4(5-sqrt(5)))/5

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- 5 p^{2} - 40 p = 64

p = - \frac{4 ( 5 + 5 )}{5}, p = - \frac{4 ( 5 - 5 )}{5}

Decimal Notation

p = - 5.78885 \dots, p = - 2.21114 \dots

Solution steps

- 5 p^{2} - 40 p = 64

Move

64

to the left side

- 5 p^{2} - 40 p - 64 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 5 ) ( - 64 )}{2 ( - 5 )}

(- 40)^{2} - 4 (- 5) (- 64) = 85

p_{1, 2} = \frac{- ( - 40 ) \pm 8 5}{2 ( - 5 )}

Separate the solutions

p_{1} = \frac{- ( - 40 ) + 8 5}{2 ( - 5 )}, p_{2} = \frac{- ( - 40 ) - 8 5}{2 ( - 5 )}

p = \frac{- ( - 40 ) + 8 5}{2 ( - 5 )} : - \frac{4 ( 5 + 5 )}{5}

p = \frac{- ( - 40 ) - 8 5}{2 ( - 5 )} : - \frac{4 ( 5 - 5 )}{5}

The solutions to the quadratic equation are:

p = - \frac{4 ( 5 + 5 )}{5}, p = - \frac{4 ( 5 - 5 )}{5}

x - 4 < - 3

x = \frac{7.1 ( 80 )}{100 - ( 80 )}

2 x^{2} = 3 - x

20 + 5 m + 12 n + 3 mn

\frac{x - 3}{x + 2} \leq 0

What are the solutions to the equation -5p^2-40p=64 ?
The solutions to the equation -5p^2-40p=64 are p=-(4(5+sqrt(5)))/5 ,p=-(4(5-sqrt(5)))/5
Find the zeros of -5p^2-40p=64
The zeros of -5p^2-40p=64 are p=-(4(5+sqrt(5)))/5 ,p=-(4(5-sqrt(5)))/5