What are the solutions to the equation (x+6)^2-3(x+6)-10=0 ?

The solutions to the equation (x+6)^2-3(x+6)-10=0 are x=-1,x=-8

Find the zeros of (x+6)^2-3(x+6)-10=0

The zeros of (x+6)^2-3(x+6)-10=0 are x=-1,x=-8

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(x + 6)^{2} - 3 (x + 6) - 10 = 0

x = - 1, x = - 8

Solution steps

(x + 6)^{2} - 3 (x + 6) - 10 = 0

Expand

(x + 6)^{2} - 3 (x + 6) - 10 : x^{2} + 9 x + 8

x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 1}, x_{2} = \frac{- 9 - 7}{2 \cdot 1}

x = \frac{- 9 + 7}{2 \cdot 1} : - 1

x = \frac{- 9 - 7}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 1, x = - 8

x^{3} - 9 x^{2} + 17 x + 15

7 a - 14

1.6

12 (x + 3) = 4 (2 x + 9) + 4 x

2 x + 5 = 3 x + 10

What are the solutions to the equation (x+6)^2-3(x+6)-10=0 ?
The solutions to the equation (x+6)^2-3(x+6)-10=0 are x=-1,x=-8
Find the zeros of (x+6)^2-3(x+6)-10=0
The zeros of (x+6)^2-3(x+6)-10=0 are x=-1,x=-8