What is factor 64n^4-192n^3+27n-81 ?

The solution to factor 64n^4-192n^3+27n-81 is (n-3)(4n+3)(16n^2-12n+9)

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factor 64n^4-192n^3+27n-81

factor

64 n^{4} - 192 n^{3} + 27 n - 81

(n - 3) (4 n + 3) (16 n^{2} - 12 n + 9)

Solution steps

64 n^{4} - 192 n^{3} + 27 n - 81

= (64 n^{4} - 192 n^{3}) + (27 n - 81)

Factor out

64 n^{3}

from

64 n^{4} - 192 n^{3} : 64 n^{3} (n - 3)

Factor out

27

from

27 n - 81 : 27 (n - 3)

= 64 n^{3} (n - 3) + 27 (n - 3)

Factor out common term

n - 3

= (n - 3) (64 n^{3} + 27)

Factor

64 n^{3} + 27 : (4 n + 3) (4^{2} n^{2} - 3 \cdot 4 n + 3^{2})

= (n - 3) (4 n + 3) (4^{2} n^{2} - 3 \cdot 4 n + 3^{2})

Simplify

(n - 3) (4 n + 3) (4^{2} n^{2} - 3 \cdot 4 n + 3^{2}) : (n - 3) (4 n + 3) (16 n^{2} - 12 n + 9)

= (n - 3) (4 n + 3) (16 n^{2} - 12 n + 9)

- \frac{1}{4} x + \frac{3}{8} \leq 1

2 x^{4} r - 72 y^{4} r

18 x^{3} y^{4} - 39 x^{4} y^{3}

- 5 x + 1 - 2 (x + 1) = 4 x + 6

64 x^{3} - 100 x

What is factor 64n^4-192n^3+27n-81 ?
The solution to factor 64n^4-192n^3+27n-81 is (n-3)(4n+3)(16n^2-12n+9)