What are the solutions to the equation a^2-5a=0 ?

The solutions to the equation a^2-5a=0 are a=5,a=0

Find the zeros of a^2-5a=0

The zeros of a^2-5a=0 are a=5,a=0

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a^{2} - 5 a = 0

a = 5, a = 0

Solution steps

a^{2} - 5 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

a_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, a_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

a = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

a = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 5, a = 0

6 t^{2} - 11 t + 4

\frac{1}{2} x + \frac{2}{3} = - \frac{2}{3}

\frac{1}{2 x} < \frac{2}{x} - 1

- 1 < 3 - 2 x \leq 5

What are the solutions to the equation a^2-5a=0 ?
The solutions to the equation a^2-5a=0 are a=5,a=0
Find the zeros of a^2-5a=0
The zeros of a^2-5a=0 are a=5,a=0