What are the solutions to the equation k^2=14 ?

The solutions to the equation k^2=14 are k=sqrt(14),k=-sqrt(14)

Find the zeros of k^2=14

The zeros of k^2=14 are k=sqrt(14),k=-sqrt(14)

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k^{2} = 14

k = 14, k = - 14

Decimal Notation

k = 3.74165 \dots, k = - 3.74165 \dots

Solution steps

k^{2} = 14

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 14, k = - 14

\frac{1}{P ( M - P )} d P

25 x^{2} - 15 = 0

\frac{244}{25} \cdot 1

x^{3} - 3 x^{2} - x + 3 > 0

9 x^{2} - 60 x y + 100 y^{2}

What are the solutions to the equation k^2=14 ?
The solutions to the equation k^2=14 are k=sqrt(14),k=-sqrt(14)
Find the zeros of k^2=14
The zeros of k^2=14 are k=sqrt(14),k=-sqrt(14)