What are the solutions to the equation x^2+4x+4=-81 ?

The solutions to the equation x^2+4x+4=-81 are x=-2+9i,x=-2-9i

Find the zeros of x^2+4x+4=-81

The zeros of x^2+4x+4=-81 are x=-2+9i,x=-2-9i

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x^{2} + 4 x + 4 = - 81

x = - 2 + 9 i, x = - 2 - 9 i

Solution steps

x^{2} + 4 x + 4 = - 81

Move

81

to the left side

x^{2} + 4 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 85}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 85 : 18 i

x_{1, 2} = \frac{- 4 \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 18 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 18 i}{2 \cdot 1}

x = \frac{- 4 + 18 i}{2 \cdot 1} : - 2 + 9 i

x = \frac{- 4 - 18 i}{2 \cdot 1} : - 2 - 9 i

The solutions to the quadratic equation are:

x = - 2 + 9 i, x = - 2 - 9 i

3 x^{2} - 5 x - 5 = 0

3 x^{2} - 49 = 0

x^{2} + 6 x y + 9 y^{2}

x^{5} - 9 x^{3} - 8 x^{2} + 72

(2 + 2 i) (2 - 2 i)

What are the solutions to the equation x^2+4x+4=-81 ?
The solutions to the equation x^2+4x+4=-81 are x=-2+9i,x=-2-9i
Find the zeros of x^2+4x+4=-81
The zeros of x^2+4x+4=-81 are x=-2+9i,x=-2-9i