What are the solutions to the equation -x^2-6x-8=-2x^2 ?

The solutions to the equation -x^2-6x-8=-2x^2 are x=3+sqrt(17),x=3-sqrt(17)

Find the zeros of -x^2-6x-8=-2x^2

The zeros of -x^2-6x-8=-2x^2 are x=3+sqrt(17),x=3-sqrt(17)

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- x^{2} - 6 x - 8 = - 2 x^{2}

x = 3 + 17, x = 3 - 17

Decimal Notation

x = 7.12310 \dots, x = - 1.12310 \dots

Solution steps

- x^{2} - 6 x - 8 = - 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} - 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 8) = 217

x_{1, 2} = \frac{- ( - 6 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 17}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 17}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 17}{2 \cdot 1} : 3 + 17

x = \frac{- ( - 6 ) - 2 17}{2 \cdot 1} : 3 - 17

The solutions to the quadratic equation are:

x = 3 + 17, x = 3 - 17

0^{\frac{4}{3}}

15 + 7 x > - 6

2 x - x^{2} = \frac{2}{3}

2 x \cdot x^{4}

- 4 + 7 > - 5

What are the solutions to the equation -x^2-6x-8=-2x^2 ?
The solutions to the equation -x^2-6x-8=-2x^2 are x=3+sqrt(17),x=3-sqrt(17)
Find the zeros of -x^2-6x-8=-2x^2
The zeros of -x^2-6x-8=-2x^2 are x=3+sqrt(17),x=3-sqrt(17)