What are the solutions to the equation 4-x^2=16-7x ?

The solutions to the equation 4-x^2=16-7x are x=3,x=4

Find the zeros of 4-x^2=16-7x

The zeros of 4-x^2=16-7x are x=3,x=4

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4 - x^{2} = 16 - 7 x

x = 3, x = 4

Solution steps

4 - x^{2} = 16 - 7 x

Move

7 x

to the left side

4 - x^{2} + 7 x = 16

Move

16

to the left side

- x^{2} + 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 12 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 12) = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 ( - 1 )}, x_{2} = \frac{- 7 - 1}{2 ( - 1 )}

x = \frac{- 7 + 1}{2 ( - 1 )} : 3

x = \frac{- 7 - 1}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 3, x = 4

\frac{5 - 4 i}{5 + i}

6 n = 4

10 s + 7 > 3 s - 8

9 x^{2} = 8 x - 3

(\frac{5}{2} + 2 i) (\frac{1}{4} - 6 i)

What are the solutions to the equation 4-x^2=16-7x ?
The solutions to the equation 4-x^2=16-7x are x=3,x=4
Find the zeros of 4-x^2=16-7x
The zeros of 4-x^2=16-7x are x=3,x=4