What are the solutions to the equation -2x^2+3x+6=0 ?

The solutions to the equation -2x^2+3x+6=0 are x=-(-3+sqrt(57))/4 ,x=(3+sqrt(57))/4

Find the zeros of -2x^2+3x+6=0

The zeros of -2x^2+3x+6=0 are x=-(-3+sqrt(57))/4 ,x=(3+sqrt(57))/4

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- 2 x^{2} + 3 x + 6 = 0

x = - \frac{- 3 + 57}{4}, x = \frac{3 + 57}{4}

Decimal Notation

x = - 1.13745 \dots, x = 2.63745 \dots

Solution steps

- 2 x^{2} + 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 6 = 57

x_{1, 2} = \frac{- 3 \pm 57}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 57}{2 ( - 2 )}, x_{2} = \frac{- 3 - 57}{2 ( - 2 )}

x = \frac{- 3 + 57}{2 ( - 2 )} : - \frac{- 3 + 57}{4}

x = \frac{- 3 - 57}{2 ( - 2 )} : \frac{3 + 57}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 57}{4}, x = \frac{3 + 57}{4}

∣ 4 + 5 c ∣ - 20 = 9

3 x^{2} - 14 x - 9 = 0

lo g_{9} (4)

2 x - 3 < 19

\frac{π}{2} + 1

What are the solutions to the equation -2x^2+3x+6=0 ?
The solutions to the equation -2x^2+3x+6=0 are x=-(-3+sqrt(57))/4 ,x=(3+sqrt(57))/4
Find the zeros of -2x^2+3x+6=0
The zeros of -2x^2+3x+6=0 are x=-(-3+sqrt(57))/4 ,x=(3+sqrt(57))/4