What are the solutions to the equation 9x(x-2)=5 ?

The solutions to the equation 9x(x-2)=5 are x=(3+sqrt(14))/3 ,x=(3-sqrt(14))/3

Find the zeros of 9x(x-2)=5

The zeros of 9x(x-2)=5 are x=(3+sqrt(14))/3 ,x=(3-sqrt(14))/3

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9 x (x - 2) = 5

x = \frac{3 + 14}{3}, x = \frac{3 - 14}{3}

Decimal Notation

x = 2.24721 \dots, x = - 0.24721 \dots

Solution steps

9 x (x - 2) = 5

Expand

9 x (x - 2) : 9 x^{2} - 18 x

9 x^{2} - 18 x = 5

Move

5

to the left side

9 x^{2} - 18 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 ( - 5 )}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 (- 5) = 614

x_{1, 2} = \frac{- ( - 18 ) \pm 6 14}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 14}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 6 14}{2 \cdot 9}

x = \frac{- ( - 18 ) + 6 14}{2 \cdot 9} : \frac{3 + 14}{3}

x = \frac{- ( - 18 ) - 6 14}{2 \cdot 9} : \frac{3 - 14}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 14}{3}, x = \frac{3 - 14}{3}

8 ab c - 16 a^{2} b^{2} c^{2}

\frac{x ^{2}}{4} + \frac{( 2 x + 5 ) ^{2}}{9} = 1

∣ x + 4 ∣ < 2

7 - (- 5) - 8 = - 6 - (- 9) + 9 - 2 X

15 \cdot 4

What are the solutions to the equation 9x(x-2)=5 ?
The solutions to the equation 9x(x-2)=5 are x=(3+sqrt(14))/3 ,x=(3-sqrt(14))/3
Find the zeros of 9x(x-2)=5
The zeros of 9x(x-2)=5 are x=(3+sqrt(14))/3 ,x=(3-sqrt(14))/3