What is x^2<= |5-6x| ?

The solution to x^2<= |5-6x| is -sqrt(14)-3<= x<= sqrt(14)-3\lor 1<= x<= 5

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x^2<= |5-6x|

x^{2} \leq ∣ 5 - 6 x ∣

- 14 - 3 \leq x \leq 14 - 3 or 1 \leq x \leq 5

Interval Notation

[- 14 - 3, 14 - 3] \cup [1, 5]

Decimal Notation

- 6.74165 \dots \leq x \leq 0.74165 \dots or 1 \leq x \leq 5

Solution steps

x^{2} \leq ∣ 5 - 6 x ∣

Find positive and negative intervals

x \leq \frac{5}{6}, x > \frac{5}{6}

Solve the inequality for each interval

- 14 - 3 \leq x \leq 14 - 3 or 1 \leq x \leq 5

2 k^{2} + 7 k - 9

2 x - \frac{5}{3} > \frac{x}{3} + 10

1 + \frac{25}{144}

x + 1 = 3 x - 2

(2 m)^{- 3}

What is x^2<= |5-6x| ?
The solution to x^2<= |5-6x| is -sqrt(14)-3<= x<= sqrt(14)-3\lor 1<= x<= 5