What are the solutions to the equation 3x^2+4x-20=0 ?

The solutions to the equation 3x^2+4x-20=0 are x=2,x=-10/3

Find the zeros of 3x^2+4x-20=0

The zeros of 3x^2+4x-20=0 are x=2,x=-10/3

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3 x^{2} + 4 x - 20 = 0

x = 2, x = - \frac{10}{3}

Decimal Notation

x = 2, x = - 3.33333 \dots

Solution steps

3 x^{2} + 4 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 20) = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 \cdot 3}, x_{2} = \frac{- 4 - 16}{2 \cdot 3}

x = \frac{- 4 + 16}{2 \cdot 3} : 2

x = \frac{- 4 - 16}{2 \cdot 3} : - \frac{10}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{10}{3}

10000 x - x^{2} = 24000000

5 < ∣ 2 x - 5 ∣ \leq 9

140 ab - 60 a^{2} + 168 b - 72 a

x^{2} (x + 4) - 8 x (x + 4) + 16 (x + 4)

\frac{1}{2} + \frac{2}{2}

What are the solutions to the equation 3x^2+4x-20=0 ?
The solutions to the equation 3x^2+4x-20=0 are x=2,x=-10/3
Find the zeros of 3x^2+4x-20=0
The zeros of 3x^2+4x-20=0 are x=2,x=-10/3