What are the solutions to the equation 15^2=x^2+(x+3)^2 ?

The solutions to the equation 15^2=x^2+(x+3)^2 are x=9,x=-12

Find the zeros of 15^2=x^2+(x+3)^2

The zeros of 15^2=x^2+(x+3)^2 are x=9,x=-12

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1 5^{2} = x^{2} + (x + 3)^{2}

x = 9, x = - 12

Solution steps

1 5^{2} = x^{2} + (x + 3)^{2}

Expand

1 5^{2} : 225

Expand

x^{2} + (x + 3)^{2} : 2 x^{2} + 6 x + 9

225 = 2 x^{2} + 6 x + 9

Switch sides

2 x^{2} + 6 x + 9 = 225

Move

225

to the left side

2 x^{2} + 6 x - 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 216 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 216) = 42

x_{1, 2} = \frac{- 6 \pm 42}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 42}{2 \cdot 2}, x_{2} = \frac{- 6 - 42}{2 \cdot 2}

x = \frac{- 6 + 42}{2 \cdot 2} : 9

x = \frac{- 6 - 42}{2 \cdot 2} : - 12

The solutions to the quadratic equation are:

x = 9, x = - 12

\frac{a ^{4} b ^{6}}{a b ^{3}}

75 x + 57 = - 75 x + 57

\frac{5}{2 - 4 i}

9 \geq 5 x + 4 \geq 2

c^{2} - 6 c

What are the solutions to the equation 15^2=x^2+(x+3)^2 ?
The solutions to the equation 15^2=x^2+(x+3)^2 are x=9,x=-12
Find the zeros of 15^2=x^2+(x+3)^2
The zeros of 15^2=x^2+(x+3)^2 are x=9,x=-12