What are the solutions to the equation x^2-4=-3 ?

The solutions to the equation x^2-4=-3 are x=1,x=-1

Find the zeros of x^2-4=-3

The zeros of x^2-4=-3 are x=1,x=-1

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x^{2} - 4 = - 3

x = 1, x = - 1

Solution steps

x^{2} - 4 = - 3

Move

4

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

4 a + 4 b + a v + b v

2^{x + 3} \leq 9^{3 x}

52 \cdot 52

\frac{a ^{- 3} b ^{4}}{a ^{- 5} b ^{5}}

\frac{2 x - 5}{x - 2} < 1

What are the solutions to the equation x^2-4=-3 ?
The solutions to the equation x^2-4=-3 are x=1,x=-1
Find the zeros of x^2-4=-3
The zeros of x^2-4=-3 are x=1,x=-1