What are the solutions to the equation 5(x-4)^2=5 ?

The solutions to the equation 5(x-4)^2=5 are x=5,x=3

Find the zeros of 5(x-4)^2=5

The zeros of 5(x-4)^2=5 are x=5,x=3

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5 (x - 4)^{2} = 5

x = 5, x = 3

Solution steps

5 (x - 4)^{2} = 5

Divide both sides by

5

(x - 4)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 1 : x = 5

Solve

x - 4 = - 1 : x = 3

The solutions to the quadratic equation are:

x = 5, x = 3

\frac{x ^{2} - 1}{5} = 7

- \frac{3}{5} - 1

(\frac{1}{3})^{7}

x^{2} + x + 1 > 0

5 < 2 x + 7 < 13

What are the solutions to the equation 5(x-4)^2=5 ?
The solutions to the equation 5(x-4)^2=5 are x=5,x=3
Find the zeros of 5(x-4)^2=5
The zeros of 5(x-4)^2=5 are x=5,x=3