What are the solutions to the equation 4n^2-9n-18=6 ?

The solutions to the equation 4n^2-9n-18=6 are n=(9+sqrt(465))/8 ,n=(9-sqrt(465))/8

Find the zeros of 4n^2-9n-18=6

The zeros of 4n^2-9n-18=6 are n=(9+sqrt(465))/8 ,n=(9-sqrt(465))/8

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4 n^{2} - 9 n - 18 = 6

n = \frac{9 + 465}{8}, n = \frac{9 - 465}{8}

Decimal Notation

n = 3.82048 \dots, n = - 1.57048 \dots

Solution steps

4 n^{2} - 9 n - 18 = 6

Move

6

to the left side

4 n^{2} - 9 n - 24 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 24) = 465

n_{1, 2} = \frac{- ( - 9 ) \pm 465}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 9 ) + 465}{2 \cdot 4}, n_{2} = \frac{- ( - 9 ) - 465}{2 \cdot 4}

n = \frac{- ( - 9 ) + 465}{2 \cdot 4} : \frac{9 + 465}{8}

n = \frac{- ( - 9 ) - 465}{2 \cdot 4} : \frac{9 - 465}{8}

The solutions to the quadratic equation are:

n = \frac{9 + 465}{8}, n = \frac{9 - 465}{8}

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What are the solutions to the equation 4n^2-9n-18=6 ?
The solutions to the equation 4n^2-9n-18=6 are n=(9+sqrt(465))/8 ,n=(9-sqrt(465))/8
Find the zeros of 4n^2-9n-18=6
The zeros of 4n^2-9n-18=6 are n=(9+sqrt(465))/8 ,n=(9-sqrt(465))/8