What are the solutions to the equation 12x^2-5x-2=0 ?

The solutions to the equation 12x^2-5x-2=0 are x= 2/3 ,x=-1/4

Find the zeros of 12x^2-5x-2=0

The zeros of 12x^2-5x-2=0 are x= 2/3 ,x=-1/4

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12 x^{2} - 5 x - 2 = 0

x = \frac{2}{3}, x = - \frac{1}{4}

Solution steps

12 x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 12 ( - 2 )}{2 \cdot 12}

(- 5)^{2} - 4 \cdot 12 (- 2) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 12}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 12}

x = \frac{- ( - 5 ) + 11}{2 \cdot 12} : \frac{2}{3}

x = \frac{- ( - 5 ) - 11}{2 \cdot 12} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{4}

0 = 16 t^{2} - 140 t + 68

\frac{1}{2} = \frac{4}{5} x - \frac{1}{4}

\frac{2}{x} - 3 \leq 5

(x - 4)^{2} + 25 = 0

t^{2} + 7 t + 12 = 0

What are the solutions to the equation 12x^2-5x-2=0 ?
The solutions to the equation 12x^2-5x-2=0 are x= 2/3 ,x=-1/4
Find the zeros of 12x^2-5x-2=0
The zeros of 12x^2-5x-2=0 are x= 2/3 ,x=-1/4