What are the solutions to the equation x^2+(-5/7)^2=1^2 ?

The solutions to the equation x^2+(-5/7)^2=1^2 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7

Find the zeros of x^2+(-5/7)^2=1^2

The zeros of x^2+(-5/7)^2=1^2 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7

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x^{2} + (- \frac{5}{7})^{2} = 1^{2}

x = \frac{2 6}{7}, x = - \frac{2 6}{7}

Decimal

x = 0.69985 \dots, x = - 0.69985 \dots

Solution steps

x^{2} + (- \frac{5}{7})^{2} = 1^{2}

Expand

x^{2} + (- \frac{5}{7})^{2} : x^{2} + \frac{25}{49}

Expand

1^{2} : 1

x^{2} + \frac{25}{49} = 1

Move

\frac{25}{49}

to the right side

x^{2} = 1 - \frac{25}{49}

Simplify

1 - \frac{25}{49} : \frac{24}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{24}{49}, x = - \frac{24}{49}

\frac{24}{49} = \frac{2 6}{7}

- \frac{24}{49} = - \frac{2 6}{7}

x = \frac{2 6}{7}, x = - \frac{2 6}{7}

0.4 \cdot 0.5

(ln (e))^{2}

(x + \frac{5}{2})^{2} - 3 = 18

(- 2.5)^{2}

6 mn - 9 m - 4 n + 6

What are the solutions to the equation x^2+(-5/7)^2=1^2 ?
The solutions to the equation x^2+(-5/7)^2=1^2 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7
Find the zeros of x^2+(-5/7)^2=1^2
The zeros of x^2+(-5/7)^2=1^2 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7