What are the solutions to the equation 2r^2=9r+5 ?

The solutions to the equation 2r^2=9r+5 are r=5,r=-1/2

Find the zeros of 2r^2=9r+5

The zeros of 2r^2=9r+5 are r=5,r=-1/2

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2 r^{2} = 9 r + 5

r = 5, r = - \frac{1}{2}

Solution steps

2 r^{2} = 9 r + 5

Move

5

to the left side

2 r^{2} - 5 = 9 r

Move

9 r

to the left side

2 r^{2} - 5 - 9 r = 0

Write in the standard form

a x^{2} + b x + c = 0

2 r^{2} - 9 r - 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 5) = 11

r_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 2}, r_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 2}

r = \frac{- ( - 9 ) + 11}{2 \cdot 2} : 5

r = \frac{- ( - 9 ) - 11}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

r = 5, r = - \frac{1}{2}

\frac{21}{7}

\frac{8 !}{3 !}

(x^{2} - 9)^{2}

z + (3 + 2 i) = 5 + 20 i

- \frac{0.8 ( 5 )}{( 0.01 ( 5 ) ^{2} + 1 ) ^{2}}

What are the solutions to the equation 2r^2=9r+5 ?
The solutions to the equation 2r^2=9r+5 are r=5,r=-1/2
Find the zeros of 2r^2=9r+5
The zeros of 2r^2=9r+5 are r=5,r=-1/2