What are the solutions to the equation x^2+13x+9=0 ?

The solutions to the equation x^2+13x+9=0 are x=(-13+sqrt(133))/2 ,x=(-13-sqrt(133))/2

Find the zeros of x^2+13x+9=0

The zeros of x^2+13x+9=0 are x=(-13+sqrt(133))/2 ,x=(-13-sqrt(133))/2

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x^{2} + 13 x + 9 = 0

x = \frac{- 13 + 133}{2}, x = \frac{- 13 - 133}{2}

Decimal Notation

x = - 0.73371 \dots, x = - 12.26628 \dots

Solution steps

x^{2} + 13 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 9 = 133

x_{1, 2} = \frac{- 13 \pm 133}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 133}{2 \cdot 1}, x_{2} = \frac{- 13 - 133}{2 \cdot 1}

x = \frac{- 13 + 133}{2 \cdot 1} : \frac{- 13 + 133}{2}

x = \frac{- 13 - 133}{2 \cdot 1} : \frac{- 13 - 133}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 133}{2}, x = \frac{- 13 - 133}{2}

\frac{4 + 3 i}{5 + 3 i}

\frac{4 x}{5} \cdot \frac{5}{6 y} + \frac{10}{21}

- \frac{2}{x} \leq x

∣ x - 1 ∣ + ∣ x - 1 ∣ = 2

\frac{5 x y ^{8}}{5 x ^{6} y ^{4}}

What are the solutions to the equation x^2+13x+9=0 ?
The solutions to the equation x^2+13x+9=0 are x=(-13+sqrt(133))/2 ,x=(-13-sqrt(133))/2
Find the zeros of x^2+13x+9=0
The zeros of x^2+13x+9=0 are x=(-13+sqrt(133))/2 ,x=(-13-sqrt(133))/2