What are the solutions to the equation 2x^2+5x-3=0 ?

The solutions to the equation 2x^2+5x-3=0 are x= 1/2 ,x=-3

Find the zeros of 2x^2+5x-3=0

The zeros of 2x^2+5x-3=0 are x= 1/2 ,x=-3

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2 x^{2} + 5 x - 3 = 0

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

2 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 2}, x_{2} = \frac{- 5 - 7}{2 \cdot 2}

x = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 5 - 7}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 3

5 m + 1 \leq 4

- a^{2} + 3 a + 10

62 \cdot 514

\frac{m - 9}{4} + 3 = \frac{m}{3}

27 x^{5} - 24 x^{4}

What are the solutions to the equation 2x^2+5x-3=0 ?
The solutions to the equation 2x^2+5x-3=0 are x= 1/2 ,x=-3
Find the zeros of 2x^2+5x-3=0
The zeros of 2x^2+5x-3=0 are x= 1/2 ,x=-3