What are the solutions to the equation 6t^2+3=0 ?

The solutions to the equation 6t^2+3=0 are t= 1/(sqrt(2))i,t=-1/(sqrt(2))i

Find the zeros of 6t^2+3=0

The zeros of 6t^2+3=0 are t= 1/(sqrt(2))i,t=-1/(sqrt(2))i

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6 t^{2} + 3 = 0

t = \frac{1}{2} i, t = - \frac{1}{2} i

Solution steps

6 t^{2} + 3 = 0

Move

3

to the right side

6 t^{2} = - 3

Divide both sides by

6

t^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - \frac{1}{2}, t = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

t = \frac{1}{2} i, t = - \frac{1}{2} i

18 x^{2} + 5 = 4

- 10 b = - 150

(x + 2) (x - 5) < 0

1. 5^{\frac{1}{10}}

\frac{16 !}{8 ! ( 16 - 8 ) !}

What are the solutions to the equation 6t^2+3=0 ?
The solutions to the equation 6t^2+3=0 are t= 1/(sqrt(2))i,t=-1/(sqrt(2))i
Find the zeros of 6t^2+3=0
The zeros of 6t^2+3=0 are t= 1/(sqrt(2))i,t=-1/(sqrt(2))i