What are the solutions to the equation 3x^2+17x-6=0 ?

The solutions to the equation 3x^2+17x-6=0 are x= 1/3 ,x=-6

Find the zeros of 3x^2+17x-6=0

The zeros of 3x^2+17x-6=0 are x= 1/3 ,x=-6

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3 x^{2} + 17 x - 6 = 0

x = \frac{1}{3}, x = - 6

Decimal Notation

x = 0.33333 \dots, x = - 6

Solution steps

3 x^{2} + 17 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 (- 6) = 19

x_{1, 2} = \frac{- 17 \pm 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 19}{2 \cdot 3}, x_{2} = \frac{- 17 - 19}{2 \cdot 3}

x = \frac{- 17 + 19}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 17 - 19}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 6

\frac{80 \cdot 20}{100}

i + 6 i

8 m^{3} n - 32 m^{2} n^{2} + 24 mn

\frac{4913}{∣ 4 x + 5 ∣ ^{2}} - ∣ 4 x + 5 ∣ \geq 0

(x + 17)^{2} = 36

What are the solutions to the equation 3x^2+17x-6=0 ?
The solutions to the equation 3x^2+17x-6=0 are x= 1/3 ,x=-6
Find the zeros of 3x^2+17x-6=0
The zeros of 3x^2+17x-6=0 are x= 1/3 ,x=-6