What are the solutions to the equation 7z^2-3z=0 ?

The solutions to the equation 7z^2-3z=0 are z= 3/7 ,z=0

Find the zeros of 7z^2-3z=0

The zeros of 7z^2-3z=0 are z= 3/7 ,z=0

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7 z^{2} - 3 z = 0

z = \frac{3}{7}, z = 0

Decimal Notation

z = 0.42857 \dots, z = 0

Solution steps

7 z^{2} - 3 z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 3)^{2} - 4 \cdot 7 \cdot 0 = 3

z_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 7}

Separate the solutions

z_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 7}, z_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 7}

z = \frac{- ( - 3 ) + 3}{2 \cdot 7} : \frac{3}{7}

z = \frac{- ( - 3 ) - 3}{2 \cdot 7} : 0

The solutions to the quadratic equation are:

z = \frac{3}{7}, z = 0

r + 2 \leq 4

\frac{x ^{2} - x - 12}{2 x - 8}

8 x^{2} - 6 x y - 9 y^{2}

∣ w ∣ < 3

What are the solutions to the equation 7z^2-3z=0 ?
The solutions to the equation 7z^2-3z=0 are z= 3/7 ,z=0
Find the zeros of 7z^2-3z=0
The zeros of 7z^2-3z=0 are z= 3/7 ,z=0