What is \sqrt[5]{4x^2}*\sqrt[5]{4x^2} ?

The solution to \sqrt[5]{4x^2}*\sqrt[5]{4x^2} is \sqrt[5]{4^2}\sqrt[5]{x^4}

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simplify \sqrt[5]{4x^2}*\sqrt[5]{4x^2}

simplify

Solution steps

Apply radical rule:

= (4 x^{2})^{\frac{1}{5}} (4 x^{2})^{\frac{1}{5}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(4 x^{2})^{\frac{1}{5}} (4 x^{2})^{\frac{1}{5}} = (4 x^{2})^{\frac{1}{5} + \frac{1}{5}}

= (4 x^{2})^{\frac{1}{5} + \frac{1}{5}}

\frac{1}{5} + \frac{1}{5} = \frac{2}{5}

= (4 x^{2})^{\frac{2}{5}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(4 x^{2})^{\frac{2}{5}} = 4^{\frac{2}{5}} (x^{2})^{\frac{2}{5}}

= 4^{\frac{2}{5}} (x^{2})^{\frac{2}{5}}

Simplify

(x^{2})^{\frac{2}{5}} : x^{\frac{4}{5}}

= 4^{\frac{2}{5}} x^{\frac{4}{5}}

- 2 x - 4 < 3 x + 21

- \frac{31}{2} (\frac{1}{100 0 ^{2}}) + \frac{31}{2}

x, - q x + p = r

lo g_{\frac{1}{4}} (3)

6 x (x - 1) = 6 - 11 x

What is \sqrt[5]{4x^2}*\sqrt[5]{4x^2} ?
The solution to \sqrt[5]{4x^2}*\sqrt[5]{4x^2} is \sqrt[5]{4^2}\sqrt[5]{x^4}