What is 11>= 3x+2\land 20-3(x+2)<= 5 ?

The solution to 11>= 3x+2\land 20-3(x+2)<= 5 is x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

11>= 3x+2\land 20-3(x+2)<= 5

11 \geq 3 x + 2 and 20 - 3 (x + 2) \leq 5

x = 3

Interval Notation

x = 3

Solution steps

11 \geq 3 x + 2 and 20 - 3 (x + 2) \leq 5

11 \geq 3 x + 2 : x \leq 3

20 - 3 (x + 2) \leq 5 : x \geq 3

Combine the intervals

x \leq 3 and x \geq 3

Merge Overlapping Intervals

x = 3

v^{2} + 21 = - 8 v + 6

8 x^{2} - 65 x + 35 = 0

ln (\frac{1}{e ^{3}})

p + \frac{1}{3} (p + 1) + \frac{1}{4} (p + 2) = \frac{5}{6}

x^{2} - 6 x y + 8 y^{2}

What is 11>= 3x+2\land 20-3(x+2)<= 5 ?
The solution to 11>= 3x+2\land 20-3(x+2)<= 5 is x=3